Question

500 ml of monoatomic gas x diffuses through a hole at pressure 4 atom and 127degree c. 1500 ml of another diatomic gas Y diffuses through a same hole at pressure 2 atm and 27 degree Celsius if time taken for both the diffusion process is same then compare the atomic weight of the two gases​

Answer 1

Explanation:

1st part: First of all we have to find out the no. of moles of gas present from the equation…

Given, P=2 atm, V=10 L, T=273 K, R=0.082 L-atm/mol*K, n=?????

Putting all the values in the above equation we get no. of moles , n=0.89 mole

2nd part: We have to find out the temp required from the given pressure…

Again, P=2.50 atm, V=10 L, R=0.082 L-atm/mol*K, n=0.89 mole, T=???????

Putting all the values in the above equation we get, T=342.5 K or, 69.5 degree C..

Thank you..