Question

5000 cal of heat is supplied to 1 litre of water. Find the rise in temperature of water. Give specific heat capacity of water =1 cal/g°C. Density of water=1g/cc

Answer 1

Volume=1lt=10^3cc
mass=density * volume=1 *10^3=10^3gm
According to qs,
5000=10^3*1*Δt
Δt=5 C

Answer 2

Answer:

Given ,

m=

200g,Q=

2000cal,Δθ=

?,

, specific heat of water

c=

1cal/g−

o

C

Now , heat required to raise the temperature of water is given by the definition of specific heat ,

Q=

mcΔθ

or

Δθ=

Q/(mc)=

2000/(200×

1)=

10

o

C