Math, asked by juhishah8797, 1 year ago

500are distributed among A B C so that B got 60rupees more than half the share of A, C got 90 rupees more than one fourth the share of A. find the shares

Answers

Answered by Anonymous
100

AnswEr :

⋆ Let the Share of A be Rs. x

⋆ B Got Rs. 60 more than half share of A

» B = 60 + ½A

» B = 60 + ½x —(¡)

⋆ C Got Rs. 90 more than ¼th share of A

» C = 90 + ¼A

» C = 90 + ¼x —(¡¡)

Now According to Question :

⇒ A + B + C = 500

⇒ x + (60 + ½x) + (90 + ¼x) = 500

  • [ From ( ¡ ) and ( ¡¡ ) ]

⇒ x + {(120 + x) /2} + {(360 + x) /4} = 500

⇒ {4x + (240 + 2x) + (360 + x)} /4 = 500

⇒ 4x + 2x + x + 240 + 360 = 500 × 4

⇒ 7x + 600 = 2000

⇒ 7x = 2000 - 600

⇒ 7x = 1400

  • Dividing Both Term by 7

x = 200

_________________________________

◑ Share of A

» Rs. 200

◑ Share of B

» 60 + ½x

» 60 + ½ × 200

» 60 + 100

» Rs. 160

◑ Share of C

» 90 + ¼x

» 90 + ¼ × 200

» 90 + 50

» Rs. 140

Share of A, B and C is Rs. 200, Rs. 160 and Rs. 140 respectively.

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