50g of saturated solution of NaCl at 30 Degree Celsius is evaporated to dryness and 13.2g of dry NaCl was obtained. find the solubility of 30 degree Celsius NaCl at in water.
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The solubility of a solute in a solvent at any temperature is defined as the maximum amount of the solute in grams which can dissolve in 100g of the solvent to form the saturated solution at that particular temperature.
Weight of solute (KCl) =13.2 g
Weight of solvent=50−13.2=36.8 g
∴ Solubility of KCl =36.313.2×100=35.869.
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