Question

52pqr(p+q)(q+r)(r+p)÷104pq(q+r)(r+p)​

Answer 1

Answer:

$\frac{r(p+q)}{2}$

Step-by-step explanation:

$\frac{52pqr(p+q)(q+r)(r+p)}{104pq(q+r)(r+p)}$

$=\frac{pqr(p+q)}{2pq}$                        

{Here, (q+r) and (r+p) get cancelled in the numerator and the denominator.

And 52/104=1/2}.

$=\frac{r(p+q)}{2}$