Question

55% of the families has a buffalo and 35% of the families has a cow and each of the 15% of the families has both a cow and a buffalo. If there are 96 families in the village, how many families have neither a cow nor a buffalo? Select one: a. 20 b. 28 c. 26 d. 24

Answer 1

Answer:

d. 24

Step-by-step explanation:

As 35% has a cow and 15% has a cow and a buffalo, the remaining 20% has just a cow.

So % of families with a buffalo or a cow (or both)

= % with a buffalo (maybe also a cow) + % with a just a cow

= 55% + 20%

= 75%

The % of families with neither a cow nor a buffalo is then 100% - 75% = 25%.

As there are 96 families, the number of families with neither a cow nor a buffalo is...

25% of 96

= 0.25 × 96

= 24