Question

554 2M
Oxalic acid is oxidised by permanganat
the reaction by ion - electron method.
+7
+3
(acid med
4
+ CÓ
reduction (+7 to +2)
oxidation (+3 to
R.HR​

Answer 1

Step-by-step explanation:

MEDIUM

Help best friend

Study later

ANSWER

Reaction involved:

KMnO

4

+H

2

C

2

O

4

+H

2

SO

4

→K

2

SO

4

+MnSO

4

+CO

2

+H

2

O

Assign the oxidation number to Mn

Let the oxidation number of Mn be 'x'.

Oxidation number of SO

4

2−

=O=−2,K=+1.

In KMnO

4

: 1+x+4×(−2)=0

x+1−8=0 or x=+7

In MnSO

4

: x+(−2)=0

x=+2in the reaction thus:

K

Mn

+7

O

4

+H

2

C

2

O

4

+H

2

SO

4

→K

2

SO

4

+

M

+2

nSO

4

+CO

2

+8H

2

O

When KMnO

4

is reduced with oxalic acid in acidic solution , the oxidation number of Mn changes from +7 to +2