Question

55ab (3a-18) (2a-6)÷22b(a-6)

Divide
​

Answer 1

Answer:

$\frac{55ab\left(3a-18\right)\left(2a-6\right)}{22b\left(a-6\right)}=15a\left(a-3\right)$

Step-by-step explanation:

$\frac{55ab\left(3a-18\right)\left(2a-6\right)}{22b\left(a-6\right)}$

=$\frac{5a\left(3a-18\right)\left(2a-6\right)}{2\left(a-6\right)}$          ........divided by 11

=$\frac{5a\left*3(a-6\right)\left*2(a-3\right)}{2\left(a-6\right)}$         ....taking common

=$\frac{30a\left(a-6\right)\left(a-3\right)}{2\left(a-6\right)}$                

=$15a\left(a-3\right)$               .........(a-6) gets canceled and 30/2=15

Plz mark as brainliest <3