Question

56. The frequency of a body executing
simple harmonic motion is 6 Hz, with an
amplitude 0.2 m. The maximum velocity
and acceleration of the body are
respectively given by
(a) 7.54 ms -1 ; 284.2 ms-2
(b) 284.2 ms-1; 7.54 ms-2
(c) 75.4 ms -1 ; 284.2 ms-2
(d) 7.54 ms-1 ; 28.42 ms-2
​

Answer 1

Answer:

option a

Explanation

v=aw

=a*2pi*n

0.2*2*3.14*6

v=7.536=7.54m/s

A=aw2

0.2*4*3.14*3.14*6*6

0.2*4*9.86*36

=283.9=284.2m/s2