Question

5a-[2a-{4c-(6a-2b+3c-2a)}]​

Answer 1

Step-by-step explanation:

$\implies$$5a-[2a-(4c-(6a-2b+3c-2a))]$

$\implies$ $5a-[2a-(4c-(4a-2b+3c))]$

$\implies$ $5a-[2a-(4c-4a+2b-3c)]$

$\implies$ $5a-[2a-(1c-4a+2b)]$

$\implies$ $5a-[2a-1c+4a-2b]$

$\implies$ $5a-6a+2b+c$

$\implies$ $\boxed{-a+2b+c}$

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Answer 2

Answer:

5a-[2a-{4c-6a+2b-3c+2a) }]

5a-[2a-{c-4a+2b }]

5a-[2a-c+4a-2b ]

5a-[6a-c-2b]

5a-6a+c+2b

-a+c+2b

c+2b-a