Question

5cosx+12sinx+12 solve the maximum and minimum value

Answer 1

i hope it helps you to its fullest

Answer 2

Answer:

maximum value = 25

minimum value = -1

Step-by-step explanation:

Since , the given expression is defined by 5 cosx + 12 sinx + 12

We have to find the maximum and minimum value of the given equation;

We know that;

Maximum value of  a cos x + b sin x  = $\sqrt{a^{2} + b^{2} }$

Minimum value of  a cos x + b sin x  = $\sqrt{a^{2} - b^{2} }$

In the given equation  5 cosx + 12 sinx + 12;

a = 5   and   b = 12

Comparing with the above equation ;

the maximum value  = $\sqrt{5^{2} + 12^{2}  } + 12$

$\sqrt{169} + 12$

= 25

So, the maximum value is 25

the minimum value = -   $\sqrt{5^{2} + 12^{2}  } + 12$

= -1

So, the minimum value is -1