5gm of rasins was kept in distilled water for 24hours the weight of soaked rasins was found 7gm find the percentage of water absorbed
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Wt. of dry raisins (W1) = 5g
wt. of soaked raisins (W2). = 7g
water absorbed by raisins. = W2 - W1
%. = ( W2 - W1)/W1. * 100
(7-5)/5. * 100
2/5. * 100
2. * 20
40%
HOPE THIS HELPS YOU
wt. of soaked raisins (W2). = 7g
water absorbed by raisins. = W2 - W1
%. = ( W2 - W1)/W1. * 100
(7-5)/5. * 100
2/5. * 100
2. * 20
40%
HOPE THIS HELPS YOU
ziafat111:
satya .cute
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