Math, asked by Anonymous, 7 months ago

5n+2 is the
is the general form of an
arthematic
sequence
find
common difference ?
the first term and 20th
term​

Answers

Answered by BrainlySmile
1

Answer- The above question is from the chapter 'Arithmetic Progressions'.

Concept used: 1) Common difference (d) = a₂ - a₁

2) aₙ = a + (n - 1)d

where aₙ = nth term or last term of an AP

a = first term of AP

n = Number of terms of AP

d = Common difference

Given question: 5n + 2 is the general form of an arithmetic sequence.

Find the common difference, the first term and 20th term​.

Solution: General form of an AP = 5n + 2

Put n = 1, a₁ = 5 (1) + 2 = 5 + 2 = 7

Put n = 2, a₂ = 5 (2) + 2 = 10 + 2 = 12

Put n = 3, a₃ = 5 (3) + 2 = 15 + 2 = 17

⇒ A.P. = 5, 12, 17, _ _ _, 5n + 2

whose first term (a) = 7

common difference (d) = 12 - 7 = 5

20th term = a + (20 - 1)d = 7 + 19(5) = 102

∴ Common difference = 5

First term = 7

Twentieth term = 102

Answered by brainlyvirat187006
2

Answer:

Answer- The above question is from the chapter 'Arithmetic Progressions'.

Concept used: 1) Common difference (d) = a₂ - a₁

2) aₙ = a + (n - 1)d

where aₙ = nth term or last term of an AP

a = first term of AP

n = Number of terms of AP

d = Common difference

Given question: 5n + 2 is the general form of an arithmetic sequence.

Find the common difference, the first term and 20th term.

Solution: General form of an AP = 5n + 2

Put n = 1, a₁ = 5 (1) + 2 = 5 + 2 = 7

Put n = 2, a₂ = 5 (2) + 2 = 10 + 2 = 12

Put n = 3, a₃ = 5 (3) + 2 = 15 + 2 = 17

⇒ A.P. = 5, 12, 17, _ _ _, 5n + 2

whose first term (a) = 7

common difference (d) = 12 - 7 = 5

20th term = a + (20 - 1)d = 7 + 19(5) = 102

∴ Common difference = 5

First term = 7

Twentieth term = 102

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