(6/√2+√3) + (3/√6+√3) - (4√3/√6+√2)
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two root three +root six by two
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=2\sqrt{3}+\sqrt{6}+3\. ( Because, √18 = √(9×2) = √9 × √2 = 3√2 and √12 = √(4×3) = √4 × √3 = 2√3 ). =0. 4.7.
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