Question

6/3 of a number exceeds its 3/5 by 8 the number is ​

Answer 1

       $\underline{\bold{Answer:}}$

       $\dfrac{40}{7}$

       $\underline{\bold{Step-by-step-explaination:}}$

       $\text{Let the number be }x$

       $\text{According to the quesiton:}$

$\implies \dfrac63x = \dfrac35x + 8$

       $\text{Simplifying...}$

$\implies 2x = \dfrac{3x+40}{5}$

       $\text{Transposing } 5 \text{ to L.H.S}$

$\implies 2x(5) = 3x+40$

       $\text{Simplifying...}$

$\implies 10x = 3x + 40$

       $\text{Transposing } 3x \text{ to L.H.S}$

$\implies 10x - 3x = 40$

       $\text{Simplifying...}$

$\implies 7x = 40$

       $\text{Transposing 7 to R.H.S}$

$\implies \boxed{x = \dfrac{40}{7}}$

Answer 2

SOLUTION

GIVEN

6/3 of a number exceeds its 3/5 by 8

TO DETERMINE

The number

EVALUATION

Let the required number = N

So by the given condition

$\displaystyle\sf{ \frac{6}{3} \times N = \frac{3}{5} \times N + 8 }$

$\displaystyle\sf{ \implies \: 2N = \frac{3N}{5} + 8 }$

$\displaystyle\sf{ \implies \: 2N - \frac{3N}{5} = 8 }$

$\displaystyle\sf{ \implies \: \frac{10N - 3N}{5} = 8 }$

$\displaystyle\sf{ \implies \: \frac{7N}{5} = 8 }$

$\displaystyle\sf{ \implies \: N = 8 \times \frac{5}{7} }$

$\displaystyle\sf{ \implies \: N = \frac{40}{7} }$

FINAL ANSWER

$\boxed{ \: \: \displaystyle\sf{ The \: required \: number = \frac{40}{7} \: \: } \: \: }$

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