Question

6 (3a+2)-5 (6a-1)=3 (a-8)-5 (7a-6)+9a​

Answer 1

Answer:-

$6(3a + 2) - 5(6a - 1) = 3(a - 8) - 5(7a - 6) + 9a$

$= > 18a + 12 - 30a + 5 = 3a - 24 - 35a + 30 + 9a$

$= > 18a - 30a + 12 + 5 = 3a - 35a +9a + 30 - 24$

$= > ( - 12a) + 17 = ( - 23a) + 6$

$= > ( - 12a) + 23a = 6 - 17$

$= > 11a = - 11$

$= > a = { \dfrac{ \cancel{ - 11} {}^{ \: \: \: \: 1} }{ \cancel{11}_{ \: \: \: \: 1}}}$

$= > a = - 1$

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Answer 2

Answer:-

$\sf\red \longrightarrow{\red {a = - 1}}$

Correct explanation:-

$\sf6(3a + 2) - 5(6a - 1) = 3(a - 8) - 5(7a - 6) + 9a$

$\sf \longrightarrow 18a + 12 - 30a + 5 = 3a - 24 - 35a + 30 + 9a$

$\sf \longrightarrow 18a - 30a + 12 + 5 = 3a - 35a +9a + 30 - 24$

$\sf \longrightarrow ( - 12a) + 17 = ( - 23a) + 6$

$\sf \longrightarrow ( - 12a) + 23a = 6 - 17$

$\sf\longrightarrow 11a = - 11$

$\sf \longrightarrow a=\dfrac{−11}{11}$

$\sf\longrightarrow a = { \dfrac{ \cancel{ - 11} {}^{ \: \: \: \: 1} }{ \cancel{11}_{ \: \: \: \: 1}}}$

$\sf \longrightarrow {a = - 1}$