6(4^x+9^x)=13×6^x then find the value of x
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Given: 6(4^x+9^x)=13×6^x
6.4^x + 6.9^x = 13×6^x
now divide both sides by 6.6^x we get
6.4^x/6.6^x + 6.9^x/6.6^x = 13×6^x /6.6^x
=> (4/6)^x +(9/6)^x = 13/6
=> (2/3)^x +(3/2)^x = 13/6
Substitute diffrent integers and test (using trail and error method)
we will get the answer= 1 and -1 (if we test by putting x=1 or -1 then only LHS=RHS)
6.4^x + 6.9^x = 13×6^x
now divide both sides by 6.6^x we get
6.4^x/6.6^x + 6.9^x/6.6^x = 13×6^x /6.6^x
=> (4/6)^x +(9/6)^x = 13/6
=> (2/3)^x +(3/2)^x = 13/6
Substitute diffrent integers and test (using trail and error method)
we will get the answer= 1 and -1 (if we test by putting x=1 or -1 then only LHS=RHS)
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