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Hi Friend !!!
================
x²-4x+1
Zeroes :
= -(-4)±√4²-4(1)(1)/2(1)
=4±√16-4 / 2
= 4±√12 / 2
= 2(2±√3)/2
= 2±√3
Hope it helps u: )
================
x²-4x+1
Zeroes :
= -(-4)±√4²-4(1)(1)/2(1)
=4±√16-4 / 2
= 4±√12 / 2
= 2(2±√3)/2
= 2±√3
Hope it helps u: )
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