Question

6.54 gram of zinc is treated with 11.5 gram of H2 S o4 calculate the volume of hydrogen evolved at STP. How much H2So4 will be left in excess

Answer 1

Explanation:

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Answer 2

Concept Introduction:-

A sentence which has a subject, verb, object, and modifiers.

Given Information:-

We have been given that $6.54$ gram of zinc is treated with $11.5$ gram of $H_2SO_4$.

To Find:-

We have to find that the volume of hydrogen evolved at STP.

Solution:-

According to the problem

$65.4 \mathrm{~g}$ of $\mathrm{Zn}$ reacts with $98 \mathrm{~g}$ of $\mathrm{H}_{2} \mathrm{SO}_{4}$

$\therefore 6.54 \mathrm{~g}$ reacts with $=\left(\frac{98}{65.4} \times 6.54\right) \mathrm{g}$ of $H_{2} \mathrm{SO}_{4}=9.8$ g of $H_2SO_4$

$\therefore$ Amount of $H_2SO_4$ left in excess $=(11.5-9.8)=1.7 \mathrm{~g}$

$98 \mathrm{~g}$ of $\mathrm{H}_{2} \mathrm{SO}_{4}$ produces $22.4$ L of $H_2$ gas at STP

$\therefore$ $9.8g$ of $\mathrm{H}_{2} \mathrm{SO}_{4}$ produces $(\frac{22.4}{98}\times 9.8)$g of $H_2$ gas at STP

$(\frac{22.4}{98}\times 9.8)=2.24L$ of $H_2$ gas at STP

Final Answer:-

$2.24$ L of $\mathrm{H}_{2} \mathrm{SO}_{4}$ is left.

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