Question

6 A bag of wheat weights 100kg. To what height
should it be raised so that its
potential energy may be 4900 Joule ? (g = 9.8 m/s*s)​

Answer 1

Answer:

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Explanation:

We know that,

U=mgh  

4900=100×9.8×h

h=  4900/100*9.8​m  

h=  4900/980m

h=5m

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Answer 2

Given :-

▪ A bag of wheat weighs 100 newton.

We took newton because it is weight.

⇒ Weight = Mass × g

⇒ Weight = kg × m/s²

⇒ Weight = kg m/s²

⇒ Weight = newton

So, Weight is measured in newton.

▪ Acceleration due to gravity, g = 9.8 m/s²

To Find :-

▪ Height at which the bag should be raised so that the potential energy of the bag be 4900 joule.

Solution :-

For finding the height, we should have mass, acceleration due to gravity and potential energy.

So, Let us find the mass of the bag,

⇒ Weight = Mass × Acceleration due to gravity

⇒ 100 = m × 9.8

⇒ m = 100 / 9.8 kg

Now, Let us find the height at which the bag should be raised, given the potential energy be 4900 joule.

⇒ Potential energy = m × g × h

⇒ 4900 = 100 / 9.8 × 9.8 × h

⇒ 4900 = 100h

⇒ h = 49 m

Hence, The bag should be raised at the height of 49 m in order to have the potential energy of 4900 joule.