6 cubical boxes A, B, C, D, E and F are arranged one above the other vertically. The boxes are arranged subject to following conditions:
(i) The number of boxes above F is the same as the number of boxes below C.
(ii) E is the only box below B.
(iii) A is not the top-most box.
In how many ways can the boxes be arranges ?
Answers
Answer:
2 ways
Step-by-step explanation:
2 ways
E is the only box below B.
=> E is at the Bottom most
& B is just above that
now maximum box above F can be 3
& minimum box below C can be
so two combinations possible
3 Boxes above F & 3 Boxes below C
& 2 Boxes above F & 2 Boxes below C
hence C & F will take (3rd & 4th Positions)
Now we left with two top position & two boxes A & D
but A is not the top-most box.
=> D is at top most & A is just below that
Hence total 2 Ways :
D
A
C
F
B
E
D
A
F
C
B
E
Answer:D A F C B E
Step-by-step explanation:
Given
Six Boxes Placed one over other
It is given no of boxes above F and below C is same i.e. they should ideally be at 3 rd and 4 th position from top.
E is the only box below B i.e. E is at the bottom .
A is not the top most therefore it should be at 2 nd Position.
Therefore D is at the top
Thus the order is D A F C B E