Question

6. Find the area of a rhombus whose side is 5 cm and whose altitude is 4.8 cm.
If one of its diagonals is 8 cm long, find the length of the other diagonal.
its area.
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Answer 1

Step-by-step explanation:

Solution

A=pq

2=10·20

2=100

100m2

Answer 2

Answer:

The area of the rhombus with side 5 cm and altitude 4.8 cm is

24 cm², and the length of the other diagonal is 6 cm.

Tip:

Let's draw the diagram of rhombus ABCD, then find the area and the length of the other diagonal.

Explanation:  

Let's draw the diagram of rhombus ABCD according to the given question.

Side of the rhombus = 5 cm  

So, AB = BC = CD = DA = 5cm (Since all the sides of a rhombus are equal)

Area of a rhombus = Base × Height (Since, rhombus is also a parallelogram)  

= 5 cm × 4.8 cm (Since, altitude = 4.8cm)  

= 24 cm²

Also,  

Area of a rhombus = (Product of the digonals)/2  

Let, DB = d1 = 8 cm and CA = d2.  

Area of a rhombus = (d1 × d2)/2  

⇒ (d1 × d2)/2 = 24  

⇒ 8 × d2 = 48  

⇒ d2 = 48/8  

⇒ d2 = 6

Hence, AC = 6 cm.