Question

6. Find the area of a sector of a circle with radius 6 cm if angle of the sector is 60°. Take= 22/7​

Answer 1

Answer:

Given:

• Radius = 6cm
• Angle of sector = 60°

Find:

• Area of sector?

Solution:

${ \boxed{ \sf{Area \: of \: sector = \frac{θ}{360} \times π {r}^{2} }}}$

$: { \implies{ \sf{Area = \frac{60}{360} \times \frac{22}{7} \times {6}^{2} }}} \\ \\ : { \implies{ \sf{Area = \frac{1}{6} \times \frac{22}{7} \times 36}}} \\ \\ : { \implies{ \sf{Area = \frac{1}{{ \cancel{6}}} \times \frac{22}{7} \times { \cancel{ 36} } }}} \\ \\ : { \sf { \implies{Area = \frac{22 \times 6}{7} }}} \\ \\ : { \sf{ \implies{Area = 18.8}}}$

Therefore,

• Area of sector = 18.8cm²

Answer 2

Step-by-step explanation:

$\mathfrak{ \huge{ \green{ \underline{given}}}} \\ \mathfrak{ \large{ \red{radius \: = \: 6 \: cm}}} \\ \mathfrak{ \large{ \red{angle \: of \: sector \: (θ) = {60}^{o}}}} \\ \mathfrak{ \huge{ \green{ \underline{to \: find}}}} \\ \mathfrak{ \large{ \red{area \: of \: sector \: = \: ?}}} \\ \mathfrak{ \huge{ \green{ \underline{formula \: to \: be \: used}}}} \\ \mathfrak{ \large{ \red{area \: of \: sector \: = \: \frac{θ}{360} \: \times \: \pi {r}^{2} }}} \\ \mathfrak{ \huge{ \green{ \underline{solution}}}} \\ \mathfrak{ \large{ \blue{area \: of \: sector \: = \frac{θ}{360} \times \pi {r}^{2}}}} \\ \mathfrak{ \large{ \blue{area \: of \: sector \: = \: \frac{60}{360} \times \frac{22}{7} \times 6 \times 6 }}} \\ \mathfrak{ \large{ \blue{area \: of \: sector \: = \: \frac{1}{6} \times \frac{22}{7} \times 6 \times 6 }}} \\ \mathfrak{ \large{ \blue{area \: of \: sector \: = \: \frac{22}{7} \times 6}}} \\ \mathfrak{ \large{ \orange{ \underline{area \: of \: sector \: = \: \frac{132}{7} {cm}^{2} }}}}$