Question

6. Find the first six terms of the sequence given by

Answer 1

HELLO DEAR,

given, $\bold{a_1 = a_2 = a_3 = 1}$.

the Equation for the series is, $\bold{a_n = a_{n - 1} + a_{n - 2}}$

where, n = 4 , 5 , 6.

n = 4,

$\bold{a_4 = a_{4 - 1} + a_{4 - 2}}$

$\bold{a_4 = 1 + 1 = 2}$

n = 5
$\bold{a_5= a_{5 - 1} + a_{5 - 2}}$

$\bold{a_5 = 2 + 1 = 3}$

n = 6
$\bold{a_6 = a_{6 - 1} + a_{6 - 2}}$

$\bold{a_6 = 3 + 2 = 5}$


I HOPE ITS HELP YOU DEAR,
THANKS

Answer 2

Solution :

It is given that ,

a1 = a2 = a3 = 1 and

an = an-1 + an-2

1 ) a4 = a3 + a2

= 1 +1

= 2

2 ) a5 = a4 + a2

= 2 + 1

= 3

3 ) a6 = a5 + a4

= 3 + 2

= 5

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