Question

6. Find the HCF of:-12ab,16bc,32bd​

Answer 1

Answer:9a2 + 4b2 + 16c2 +12ab-16bc-24ca-

3a + 2a + 4c +(2x3a×2a)-(2×2a×4c)-(2×4c×3a)

so ,

a=3a

b=2b

c=4c

then the formula is (a+b+c)whole square

put the value of a b c

it gives- (3a+2b+4c) whole square

I hope it will helps

Step-by-step explanation: