Question

6. How many Joules of heat is needed in
raising the temperature of 250 gm of water
from 20°C to 55°C ?
[ 1
1) 8750
2) 87.50
3) 36,750
4) 3675​

Answer 1

H = mcΔt = (250/1000 * 35 * 4,200) J = 36750 J

Answer 2

Answer:

The secret to this is in the constant called Specific Heat Capacity of Water, which is essentially 4.186 joules per gram, per °C.

Now, We have

250 gram of water

Temperature Difference = 100 °C -35°C= 65 °C

All you need to do is essentially multiply specific Heat Capacity with the two values above.

The magnitude of Heat in Joules =

(4.186 J / g °C) x (250 g) x (65°C) = 68,022.5 Joules

You can convert this into Kilo Joules by dividing it with 1,000, and further into Mega Joules by dividing again with 1,000.