Question

6. If x= 1, y = -1, z = 3, a = 1, b = -2, C=2, find the value of
x³+y³-3xyz+a²(b-c)​

Answer 1

Answer:

5

Step-by-step explanation:

A|Q

x³+y³-3xyz+a²(b-c)

=> 1³ + (-1)³ - 3(1)(-1)(3) + 1²{(-2)-2}

=> 1 - 1 + 9 + 1{ -4}

=> 9 - 4

=> 5