Math, asked by shivampanwar471, 11 months ago

6. Prove that
sin (A – B)
sin (A + B)
tan A – tan B
tan A + tan B

Answers

Answered by Anonymous

4

Answer:

Your question lacks fundamentals of Mathematics!

Answered by rani49035

0

Answer:

sin (A – B) = sinAcosB - sinBcosA

sin (A – B) = sinAcosB - sinBcosAsin (A + B) = sinAcosB + sinBcosA

tan(A+B) = (tan A + tan B)/1-tanA.tanB

tan A + tan B= tan(A+B).(1-tanA.tanB)

tan A - tan B= tan(A-B).(1+tanA.tanB)

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