Question

6 root 12 divide root 3 into 3 root 2​

Answer 1

Answer:

Here, it is step-wise explanation of your question .

Answer 2

Answer:

The value of the expression is

$\frac{6 \sqrt{12} }{ \sqrt{3} \times 3 \sqrt{2} } =2\sqrt{2}$

Step-by-step explanation:

The given expression of irrational numbers is

$\frac{6 \sqrt{12} }{ \sqrt{3} \times 3 \sqrt{2} }$

To solve this expression,we shall rationalise the denominator first by multiplying and dividing the number with a rationalising factor which consists of irrational terms.It is done in the following way

$\frac{6 \sqrt{12} }{ \sqrt{3} \times 3 \sqrt{2} } \times \frac{ \sqrt{2}. \sqrt{3} }{ \sqrt{2} . \sqrt{3} }$

To solve this we shall use the identity as shown below

$\sqrt{a} \times \sqrt{b} = \sqrt{ab}$

Hence,the expression becomes as shown below

$\frac{6\sqrt{12 \times 2 \times 3} }{3 \sqrt{2 \times 3 \times 2 \times 3} } \\ = \frac{2\sqrt{3 \times 4 \times 2 \times 3} }{2 \times 3} \\ =\frac{\sqrt{3^{2}\times2^{2}\times2 } }{3}=\frac{3\times2\times\sqrt{2} }{3} = 2 \sqrt{2}$

Therefore,the value of the expression is

$\frac{6 \sqrt{12} }{ \sqrt{3} \times 3 \sqrt{2} } =2\sqrt{2}$

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