6 x² + 3x+4= 0
then x=?
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The equation has imaginary roots and the value of x will be imaginary.
Given equation- 6x²+3x+4=0
For the given equation a = 6 , b = 3 , c = 4
First we will find the determinant of the equation
D = b²-4ac
=> D = 9 - 96
D < 0
The value of the determinant of the equation is negative which means that the roots of the given equation are imaginary.
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