62.5×10^18 elctrons per s3cond are flowing throigh a wire of area of cross section0.1m^2 then what is the value of current flowing will be
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I=neAV
I(current)=(62.5×10^18)×(1.6×10^-19)×(0.1)×10
=10 ampere
where
n=No.of electrons=62.5×10^18 (given)
e=charge of 1 electron=1.6×10^-19
A=cross sectional area of conductor=0.1 m^2 (given)
V=drift velocity=10 m/s (appr.)
djsnake:
could u just explain it
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