Question

64 c cube + 27y cube

Answer 1

64c³+27y³
(4c)³+(3y)³
use the formula (a³+b³)=(a+b)(a²-ab+b²)
a=4c,b=3y
(4c+3y)((4c)²-(4c)(3y)+(3y)²)
(4c+3y)(16c²-12cy+9y²)

Answer 2

Guy

given

• 64c³ + 27y³

first we needs a formula which is

a³ + b³ = ( a + b ) ( a² - ab + b² )

now

64c³ + 27y³

= ( 4c )³ + ( 3y )³

= ( 4c + 3y ) { ( 4c )² - 4c . 3y + ( 3y )² }

= ( 4c + 3y ) ( 16c² - 12cy + 9y² )

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