64 c cube + 27y cube
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Answered by
2
64c³+27y³
(4c)³+(3y)³
use the formula (a³+b³)=(a+b)(a²-ab+b²)
a=4c,b=3y
(4c+3y)((4c)²-(4c)(3y)+(3y)²)
(4c+3y)(16c²-12cy+9y²)
(4c)³+(3y)³
use the formula (a³+b³)=(a+b)(a²-ab+b²)
a=4c,b=3y
(4c+3y)((4c)²-(4c)(3y)+(3y)²)
(4c+3y)(16c²-12cy+9y²)
kristigupta:
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please
Answered by
1
Guy
given
• 64c³ + 27y³
first we needs a formula which is
a³ + b³ = ( a + b ) ( a² - ab + b² )
now
64c³ + 27y³
= ( 4c )³ + ( 3y )³
= ( 4c + 3y ) { ( 4c )² - 4c . 3y + ( 3y )² }
= ( 4c + 3y ) ( 16c² - 12cy + 9y² )
====================================
given
• 64c³ + 27y³
first we needs a formula which is
a³ + b³ = ( a + b ) ( a² - ab + b² )
now
64c³ + 27y³
= ( 4c )³ + ( 3y )³
= ( 4c + 3y ) { ( 4c )² - 4c . 3y + ( 3y )² }
= ( 4c + 3y ) ( 16c² - 12cy + 9y² )
====================================
i am very thankful to you
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