64x^ + 16x + 1 how do we solve it
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Answered by
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64x^2 + 8x +8x + 1
8x(8x +1)+1(8x+1)
(8x+1)(8x+1). are the factors of the asked question...
Now the zeroes are ::
x = -1/8 for both factors
Mark as Brainlist
8x(8x +1)+1(8x+1)
(8x+1)(8x+1). are the factors of the asked question...
Now the zeroes are ::
x = -1/8 for both factors
Mark as Brainlist
nark:
I need its zeroes
now will be it helpful to you
Answered by
2
May it is 64x²+16x+1...... so this is your answer..
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