67. Total number of optically active compound(s) formed
in the given reaction is
CH3CH=CHC2H5
(1) 4
(3) 2
(2) 3
(4) Zero
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Answered by
1
Answer:
Option 1 ie. 4 is right
Explanation:
In the above image
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Answer:
option 1 i.e. 4 is correct answer
Explanation:
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