Question

6th Quesion kardo please solve nahi ho pa raha.......

Answer 1

Answer:

4N

Explanation:

v2-u2= 2as

0-20²=2a x 50

-400 = 100a

-400/100=a

a = - 4m/s²

F=ma

=1kg×4m/sec²

=4N.

Force applied by stone on the surface =Force applied by surface on the stone.(Newton's 3rd law)

So,the force of friction between ice and stone is 4N