Question

6x^2+x-12=0 plzz answer the question​

Answer 1

Answer:

$6 {x}^{2} + x - 12 = 0 \\ \\ \\ 6 {x}^{2} - 8x + 9x - 12 = 0 \\ \\ \\ \\ = > 2x(3 x- 4) + 3(3x - 4) \\ \\ = = > (2x + 3)(3x - 4) = 0 \\ \\ \\ = > 2x + 3 = 0 \\ \\ x = \frac{ - 3}{2} \\ \\ 3x - 4 = 0 \\ \\ x = \frac{4}{3}$

please mark me brainlist ✔️✔️

Answer 2

Answer:

$6 {x}^{2} + x - 12 = 0 \\ 6 {x}^{2} + 9x - 8x - 12 = 0 \\ 3x(2x + 3) - 4(2x + 3) = 0 \\ (3x - 4)(2x + 3) = 0 \\ \\ \\ x = \frac{4}{3} \: \: \: or \: \: \: \frac{ - 2}{3}$

HOPE IT HELPS......

PLEASE MARK ME AS BRAINLIEST ANSWER.....