Math, asked by MohammedAamir4765, 11 months ago

(√7-2)/(√7+2)=a√7+b எ‌னி‌ல் a ம‌ற்று‌ம் b‌ன் ம‌‌தி‌ப்புகளை‌‌க் கா‌ண்க

Answers

Answered by Avni2348
0

Answer:

( \sqrt{7 - 2)( \sqrt{7 + 2) = a \sqrt{7 + b} } }

Answered by steffiaspinno
0

i)a=\frac{-4}{3}  ii)b=\frac{11}{3}

விளக்கம்:

\frac{\sqrt{7}-2}{\sqrt{7}+2} )=a√7+b

=\frac{\sqrt{7}-2}{\sqrt{7}+2} \times \frac{\sqrt{7}-2}{\sqrt{7}-2}

=\frac{(\sqrt{7}-2)^{2}}{(\sqrt{7})^{2}+2^{2}}

=\frac{(\sqrt{7}-2)^{2}-2(2) \sqrt{7}}{7-4}

=\frac{7+4-4 \sqrt{7}}{3}

=\frac{11-4 \sqrt{7}}{3} =a \sqrt{7}+b

\frac{11}{3}-\frac{4 \sqrt{7}}{3}=a \sqrt{7}+b

\frac{7 \sqrt{7}}{3}  = a \sqrt{7}+b

7\sqrt{7} =3(a \sqrt{7}+b)

a=\frac{-4}{3}

b=\frac{11}{3}

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