7÷75 is this terminating or not give reason
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=7/75
=7/(5²×3)
The denominator is not of the form 2^m×5^n. So it will have a non-terminating decimal expansion.
=7/(5²×3)
The denominator is not of the form 2^m×5^n. So it will have a non-terminating decimal expansion.
Answered by
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Heya user
7/75 will have a non-terminating repeating decimal expansion .
As we know that the fraction whose denominator's prime factorization is of the form 2^m × 3^n, where m and n are whole numbers will have a terminating decimal expansion. But 75 = 3 × 5^2 , which is not of the form 2^m × 3^n.
So, it will not have a terminating decimal expansion.
Hope this will help☺☺
7/75 will have a non-terminating repeating decimal expansion .
As we know that the fraction whose denominator's prime factorization is of the form 2^m × 3^n, where m and n are whole numbers will have a terminating decimal expansion. But 75 = 3 × 5^2 , which is not of the form 2^m × 3^n.
So, it will not have a terminating decimal expansion.
Hope this will help☺☺
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