Question

7. Find the least number of five digits
which on dividing by 10, 20, 30, 40 and
50 leaves a remainder of 8 in each case.​

Answer 1

Answer:

10208

Step-by-step explanation:

we will take LCM of 10 20 30 40 and 50 which is 600 now we must make it 5 digit

lcm of 10,20,30,40 and 50 = 600

lets multiply 600 to get 5 digit no.

least 5 digit no. is 10000

we will multiply 600 by 17 to get 10200

we will add 8 to get 10208