Question

7. For what value of k, the equation x2 + (k + 1)x + (k + 4) = 0 has equal roots?

Answer 1

Answer:

Step-by-step explanation:

Answer 2

ax^2+bx+c = 0

x^2+(k+1)x+(k+4) = 0

a = 1 , b = k+1 , c = k+4

formula ,

b^2- 4ac = 0

(k+1)^2 - 4×1×(k+4) = 0

k^2+1+2k- 4k- 16 = 0

k^2-2k-15 = 0

(k-5) , (k+3) = 0

k = 5 , -3