Question

7. Identify the error and correct the statements.
a) (–12) ÷ 0 = 0_________________________
b) (–57) × (–19) + 57 = 57 × [(–19) + 1]
=57x18
= 1026

Answer 1

Given : a) (–12) ÷ 0 = 0_________________________

b) (–57) × (–19) + 57 = 57 × [(–19) + 1]

=57x18

= 1026

To Find :  Identify the error

Solution:

a) (–12) ÷ 0 = 0

Number divided by 0 are infinite   Hence

(–12) ÷ 0  = ∞

or

0  ÷  (-12)  = 0

b) (–57) × (–19) + 57 = 57 × [(–19) + 1]

=57x18

= 1026

taking 57 common leaves -1 and - 19 in multiples which results in +19  and not in - 19  

and then 19 + 1 = 20        not 18

on taking  57 common  

(–57) × (–19) + 57

= 57[ ( -(-19) +  1}

= 57 ( 19 + 1)    

= 57 ( 20)

= 1140

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