Question

9)There are some cowherds in a field. Cows and cowherds have 98 legs and 26 heads. How many cows and cowboys are there?​

Answer 1

Answer:

Let the numbers of cows be 'A'

and number of Cowboys be 'B'

4A + 2B = 98 [°.° cow has four legs and man has two legs]-------------- (1)

A + B = 26 [°.° both cow and man has one head each]-----------------(2)

.°. A = 26 - B [from eq. 2]

now, substituting the value of A = 26 - B in eqn. 1, we get

4 ×( 26 - B) + 2B = 98

= 92 - 4B +2B = 98

= - 2B = 98 - 92

= - 2B = 6

= B = 6/-2 = -3

.°. The number of cowboys = 3 [ here neglect the negative sign]

again, number of cow = A = 26 - B

= A = 26-3 = 23

.°. There are 23 cows in the field.

verification:

4×23+2×3= 98

23+3=26

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