Question

7. If a ß are zeros of polynomial f(x) = x2 + px + q then find a polynomial
having 1/a and 1/b as its zeros.
​

Answer 1

Answer:

• -p/q

Explanation:

Given polynomial,

⇒ x² + px + q

On comparing with the general form of equation ax² + bx + c

• a = 1
• b = p
• c = q

Then,

• α + β = -b/a = -p
• αβ = c/a = q

Finding :

⇒ 1/α + 1/β

⇒ α + β/αβ

On substituting the values,

⇒ -p/q

Hence,

⇒ 1/α + 1/β = -p/ q