The rate of increase of the circumference of a
circle and that of the area are 3 and 4
respectively, then its radius is
Answers
Answer:
fontsize1810Area is increased by 300 percent.
Step-by-step explanation:
Let r units and r' units denote the radius of the given circle with circumference 4π and 8π respectively.
Then, we have
\begin{gathered}2\pi r=4\pi\\\\\Rightarrow r=\dfrac{4\pi}{2\pi}\\\\\Rightarrow r=2\end{gathered}
2πr=4π
⇒r=
2π
4π
⇒r=2
and
\begin{gathered}2\pi r^\prime=8\pi\\\\\Rightarrow r^\prime=\dfrac{8\pi}{2\pi}\\\\\Rightarrow r^\prime=4\end{gathered}
2πr
′
=8π
⇒r
′
=
2π
8π
⇒r
′
=4
Now, the area of the circle with radius 2 units is
A_1=\pi r^2=\pi \times2^2=4\piA
1
=πr
2
=π×2
2
=4π
and the area of the circle with radius 4 units is
A_2=\pi (r^\prime)^2=\pi \times4^2=16\piA
2
=π(r
′
)
2
=π×4
2
=16π
Therefore, the percent increase in the area of the circle is
\begin{gathered}\dfrac{A_2-A_1}{A_1}\times100\%\\\\\\=\dfrac{16\pi-4\pi}{4\pi}\times100\%\\\\=\dfrac{12\pi}{4\pi}\times100\%\\\\=300\%.\end{gathered}
A
1
A
2
−A
1
×100%
=
4π
16π−4π
×100%
=
4π
12π
×100%
=300%.
Thus, the area of the circle is increased by 300%.
hope it helps
radius is 45 cm longest ok understood