Math, asked by khushnumapraveen42, 15 days ago

7. If x = 2 and y = 4, find the value of: (b) x3+y3+3xy2+3x2y
Please give me the answer with process.​

Answers

Answered by ayushi1665
0

Answer:

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Step-by-step explanation:

x3 + y3 + 3xy2 + 3x2y

=2*3 + 4*3 + 3*2*4*2 + 3*2*2*4

=6 + 12 + 48 + 48

=114

Answered by rupkathajangipara202
0

Answer:

x = 216

Step-by-step explanation:

x =2, y = 4

X3+Y3+3xy2+3x2y [as, x =2 and y = 4]

= 2^3+4^3+3.2.(4)^2+3.(2)^2.4

= 8+64+96+48

=216

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