Question

7. In the hare-tortoise race, the hare ran for 2 min at a speed of 7.5 km/h, slept for 56 min and ran for 2 min
at a speed of 7.5 km/h. Find the average speed of the hare in the race.​

Answer 1

$\boxed{\huge{\rm{\green{SoLution \rightarrow}}}}$

$\sf{D1 = 7.5\times \dfrac{2}{60}= 0.25km}$

$\sf{D2= 7.5\times \dfrac{2}{60}= 0.25km}$

$\bf{Total \ Distance= 0.25+0.25=0.50km}$

$\bf{Total\ time\ taken = 2+2+56 = 60min= 1 Hr}$

$\boxed{\sf{\pink{Average\ speed =\dfrac{total\ distance}{total\ time}}}}$

$\sf{Average\ speed= \dfrac{0.5}{1}= 0.5 km/hr}$

$\underline{\bf{\therefore Average\ speed= 0.5km/h }}$

In m/s=>

$\bf{Average\ speed =0.138m/s}$

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Answer 2

Explanation:

{\boxed{\huge{\rm{\green{SoLution \rightarrow}}}}

SoLution→

{\sf{D1 = 7.5\times \dfrac{2}{60}= 0.25km}D1=7.5×

60

2

=0.25km

{\sf{D2= 7.5\times \dfrac{2}{60}= 0.25km}D2=7.5×

60

2

=0.25km

{\bf{Total \ Distance= 0.25+0.25=0.50km}Total Distance=0.25+0.25=0.50km

{\bf{Total\ time\ taken = 2+2+56 = 60min= 1 Hr}Total time taken=2+2+56=60min=1Hr

{\boxed{\sf{\pink{Average\ speed =\dfrac{total\ distance}{total\ time}}}}

Average speed=

total time

total distance

{\sf{Average\ speed= \dfrac{0.5}{1}= 0.5 km/hr}Average speed=

1

0.5

=0.5km/hr

{\underline{\bf{\therefore Average\ speed= 0.5km/h }}

∴Average speed=0.5km/h

In m/s=>

{\bf{Average\ speed =0.138m/s}Average speed=0.138m/s

c

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