Question

what is the probability that a leap year selected at random will contain either 53 wednesday or 53 Friday? Why can't we have Tue,wed Wed,Thur Thur,Fri Fri,sat Plz explain correctly I will surely mark brainliest

Answer 1

Step-by-step explanation:

Therefore possibilities 3, 4, and 5 from above will have either 53 Thursdays or 53 Fridays. So 3 possibilities out of 7: the answer is 3/7 or about 43% probability that a leap year selected at random will have either 53 Thursdays or 53 Fridays.

please mark me as brainliest and follow me

Answer 2

Answer:

probability of Wednesday and Friday will be:3/7 approximately....

Step-by-step explanation:

we can't take tue, Wed Wed, Thur Thur, Fri Fri, sat because leap year can't contain 53 of these i think so

Mark me as the Brainliest!!!!