Question

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7. sec^2 A + tan A =13 then tan A = ??​

Answer 1

hope this helps u

we know that

sec²A-tan²A=1

⇒sec²A= 1 +tan²A-------(1)

sec²A+tanA= 13

 1 +tan²A+tanA = 13 by using 1

tan²A+tan A = 13-1

tan²A+tan A= 12

tan²A+tan A-12=0

tan²A+4tan A-3tanA-12

tan A(tan A+4) -3(tanA+4)

(tan A+4) = 0            (tan A-3)=0

tan A = -4,3

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