Two beads P and Q, free to slide on a smooth light horizontal rod, are connected by a
string (between P and Q) of lengthl = 2.5m. Masses of the beads are
mp = 2 kg and me = 3 kg respectively. The whole setup is rotated with an angular velocity
o=1rad / s about a vertical axis such that the system of beads is in equilibrium with
respect to the rotating rod. Then, tension in the connecting string PQ is
Р
Q
string
A
1
· B
A) 1N
B) 2 N
C) 3N
D) 4N
Answers
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0
Answer:
Explanation:
is called a newton (N), and from F = ma we see that 1 N = 1 kg m/s2. ... The friction force between two objects is extremely complicated on a ... a free-body diagram shows all of the external forces (that is, forces due to ... A mass m is connected to the end of a massless string of length ℓ. ... i = 2ad, or d = v0t − at2/2 with t =.
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