Question

7) Simplify the following.
(i) (x + a)(x-a)(x + a')
(ii) (a? -1) (o? + 1) (0* + 1)
(iii) (2x + y) (2x - y) (4x + y)​

Answer 1

Answer:

Step-by-step explanation:

1) In the first method, you distribute (x-a) to each term in (x-b).

(x-a)(x-b)=x(x-a)-b(x-a)

The second step in that method is to multiply.

x(x-a)-b(x-a)=(x^2-ax)-(bx-ab)

Third, distribute the negative to the quantity (bx-ab).

(x^2-ax)-(bx-ab)=x^2-ax-bx+ab

This results in an answer of x^2-ax-bx+ab

The second way is the FOIL method.

First: x*x=x^2

Outer: x*-b=-bx

Inner: -a*x=-ax

Last: -a*-b=ab

You then add each quantity.

x^2-ax-bx+ab

________________________

This is 3rd answer I don't know 2nd one sorry

Solve equation [2] for the variable y

[2] y = 4x + 2

// Plug this in for variable y in equation [1]

[1] 2x - (4x+2) = 0

[1] -2x = 2

// Solve equation [1] for the variable x

[1] 2x = - 2

[1] x = - 1

// By now we know this much :

x = -1

y = 4x+2

// Use the x value to solve for y

y = 4(-1)+2 = -2

Solution :

{x,y} = {-1,-2}

Hope it helps

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